Between neutron scattering and electromagnetic waves scattering (like X-rays or light), which of the two would be more appropriate for investigating the scattering cross section of the atom as a whole, and which would be more appropriate for investigating the nucleus of an atom? Which one will depend on \(Z\), the atomic number?

Short Answer

Expert verified
Answer: Electromagnetic wave scattering is more suitable for investigating the scattering cross section of the atom as a whole, while neutron scattering is more appropriate for investigating the nucleus of an atom specifically. The effectiveness of electromagnetic wave scattering techniques depends on the atomic number (Z), whereas neutron scattering does not depend on Z.

Step by step solution

01

Neutron Scattering vs. Electromagnetic Wave Scattering

Neutron scattering and electromagnetic wave scattering are two different processes that can be used to investigate the properties of atoms, such as their scattering cross sections. Neutron scattering uses neutrons (neutral particles) to probe the atomic structure, while electromagnetic wave scattering uses waves, such as X-rays or light, which interact with the charged components of the atom (i.e. electrons and the nucleus).
02

Scattering Cross Section of Atom as a Whole

When it comes to investigating the scattering cross section of the atom as a whole, electromagnetic waves scattering techniques are more appropriate. This is because electromagnetic waves, such as X-rays or light, interact with both the electrons and the nucleus, providing information about the overall atomic structure.
03

Investigating the Nucleus of an Atom

For investigating the nucleus of an atom specifically, neutron scattering is more appropriate. Since neutrons are neutral particles, they do not interact with the electron cloud of the atom, and thus can provide more accurate and specific information about the atomic nucleus.
04

Dependence on Atomic Number (Z)

The effectiveness of electromagnetic wave scattering techniques, like X-rays and light, depends on the atomic number (Z) of the sample. This is because the scattering cross section for electromagnetic waves is proportional to the square of the atomic number, as it is dependent on the number of electrons present in the atom. On the other hand, neutron scattering does not depend on Z, as neutrons specifically interact only with the nucleus of the atom without being affected by the electron distribution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The fundamental observation underlying the Big Bang theory of cosmology is Edwin Hubble's 1929 discovery that the arrangement of galaxies throughout space is expanding. Like the photons of the cosmic microwave background, the light from distant galaxies is stretched to longer wavelengths by the expansion of the universe. This is not a Doppler shift: Except for their local motions around each other, the galaxies are essentially at rest in space; it is the space itself that expands. The ratio of the wavelength of light \(\lambda_{\text {rec }}\) Earth receives from a galaxy to its wavelength \(\lambda_{\text {emit }}\) at emission is equal to the ratio of the scale factor (e.g., radius of curvature) \(a\) of the universe at reception to its value at emission. The redshift \(z\) of the light-which is what Hubble could measure - is defined by \(1+z=\lambda_{\text {rec }} / \lambda_{\text {emit }}=a_{\text {rec }} / a_{\text {emit }}\). a) Hubble's Law states that the redshift \(z\) of light from a galaxy is proportional to the galaxy's distance from us (for reasonably nearby galaxies): \(z \cong c^{-1} H \Delta s\), where \(c\) is the vacuum speed of light, \(H\) is the Hubble constant, and \(\Delta s\) is the distance of the galaxy. Derive this law from the first relationships stated in the problem, and determine the Hubble constant in terms of the scale-factor function \(a(t)\). b) If the present Hubble constant has the value \(H_{0}=72(\mathrm{~km} / \mathrm{s}) / \mathrm{Mpc},\) how far away is a galaxy, the light from which has redshift \(z=0.10\) ? (The megaparsec \((\mathrm{Mpc})\) is a unit of length equal to \(3.26 \cdot 10^{6}\) light-years. For comparison, the Great Nebula in Andromeda is approximately 0.60 Mpc from us.)

Which of the following particles does not have integer spins? a) photon b) \(\pi\) meson c) \(\omega\) meson d) \(\nu_{\mathrm{e}}\) lepton

An exchange particle for the weak force is the a) photon. b) meson. c) \(W\) boson. d) graviton. e) gluon.

An electron-positron pair, traveling toward each other with a speed of \(0.99 c\) with respect to their center of mass, collide and annihilate according to \(e^{-}+e^{+} \rightarrow \gamma+\gamma\). Assuming the observer is at rest with respect to the center of mass of the electron-positron pair, what is the wavelength of the photons?

Draw a quark-level Feynman diagram for the decay of a neutral kaon into two charged pions, \(K^{0} \rightarrow \pi^{+}+\pi^{-}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free