According to the standard notation, find the number of protons, nucleons, neutrons, and electrons of \({ }_{54}^{134}\) Xe.

Short Answer

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Question: Determine the number of protons, nucleons, neutrons, and electrons in the Xenon (Xe) isotope with the atomic notation \({}_{54}^{134}\) Xe. Answer: In the \({}_{54}^{134}\) Xe isotope, there are 54 protons, 134 nucleons, 80 neutrons, and 54 electrons (in a neutral atom).

Step by step solution

01

Identify the atomic number and the mass number

In the given notation \({}_{54}^{134}\) Xe, the lower number (54) represents the atomic number, and the upper number (134) represents the mass number (also called nucleon number).
02

Find the number of protons

In any element, the atomic number is equal to the number of protons. Therefore, in \({}_{54}^{134}\) Xe, there are 54 protons.
03

Find the number of neutrons

The mass number (nucleon number) is the sum of protons and neutrons in the nucleus. We can find the number of neutrons by subtracting the number of protons from the mass number: 134 - 54 = 80. So, there are 80 neutrons in \({}_{54}^{134}\) Xe.
04

Find the number of electrons

In a neutral atom, the number of electrons is equal to the number of protons (because they balance out the positive and negative charges). Since we found the number of protons to be 54, we can conclude that there are 54 electrons in a neutral \({}_{54}^{134}\) Xe atom.
05

Summary

For the \({}_{54}^{134}\) Xe isotope, the number of protons is 54, the number of neutrons is 80, the number of nucleons is 134 (mass number), and the number of electrons is 54 (for a neutral atom).

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