Which of the following is not a valid potential energy function for the spring force \(F=-k x ?\) a) \(\left(\frac{1}{2}\right) k x^{2}\) b) \(\left(\frac{1}{2}\right) k x^{2}+10 \mathrm{~J}\) c) \(\left(\frac{1}{2}\right) k x^{2}-10 \mathrm{~J}\) d) \(-\left(\frac{1}{2}\right) k x^{2}\) e) None of the above is valid.

Short Answer

Expert verified
(a) \((\frac{1}{2}) k x^{2}\) (b) \((\frac{1}{2}) k x^{2} + 10\) (c) \((\frac{1}{2}) k x^{2} - 10\) (d) \(-(\frac{1}{2}) k x^{2}\) Answer: (d) \(-(\frac{1}{2}) k x^{2}\)

Step by step solution

01

Identify the valid potential energy functions

We already know that the standard potential energy function for spring force is \(U(x)=\left(\frac{1}{2}\right) k x^{2}\). Adding or subtracting a constant value, in this case \(10 \mathrm{~J}\), does not change the fact that the potential energy function is still valid. So, we can say that options a), b), and c) are valid potential energy functions.
02

Examine the remaining option

Now, we only have to check option d) to determine whether it is a valid potential energy function for the spring force or not. The given function is \(U(x)=-\left(\frac{1}{2}\right) k x^{2}\). Comparing it to the standard potential energy function, we can see that it has a negative sign in front of the expression. This means that the potential energy will be negative, which is not possible for a spring system, as the potential energy should always be non-negative.
03

Determine the answer

Based on our analysis, we can conclude that option d) is not a valid potential energy function for the spring force. Therefore, the correct answer is: (d) \(-\left(\frac{1}{2}\right) k x^{2}\)

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