The center of mass of an irregular rigid object is always located a) at the geometrical center of c) both of the above the object. d) none of the above b) somewhere within the object.

Short Answer

Expert verified
Answer: The center of mass of an irregular rigid object is always located somewhere within the object.

Step by step solution

01

Define center of mass

The center of mass is a point within or near an object where the object's mass is considered to be concentrated. In general, the center of mass can be located by the average position of all particles that make up the object.
02

Evaluate option a)

In option a), it's proposed that the center of mass is always located at the geometrical center of the object. This may be true for symmetric objects with uniform mass distribution, but for irregular objects, the mass may be unevenly distributed. In such cases, the center of mass will not be at the geometrical center. So, option a) is not correct.
03

Evaluate option b)

In option b), it's proposed that the center of mass is always located somewhere within the object. This is a more general statement, as it accounts for both regular and irregular rigid objects. For irregular objects with uneven mass distribution, their center of mass may not be at the geometrical center but still located within the object. This option seems correct.
04

Evaluate option c)

Option c) suggests that both options a) and b) are correct. However, we have already evaluated both options and determined that option a) is not always correct. Therefore, option c) cannot be correct.
05

Evaluate option d)

Option d) states that none of the above options are correct. Since we have found that option b) is correct, option d) is not correct. #Conclusion#From our analysis of each option, we found that option b) is the correct one. The center of mass of an irregular rigid object is always located somewhere within the object.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A cart running on frictionless air tracks is propelled by a stream of water expelled by a gas-powered pressure washer stationed on the cart. There is a \(1.00-\mathrm{m}^{3}\) water tank on the cart to provide the water for the pressure washer. The mass of the cart, including the operator riding it, the pressure washer with its fuel, and the empty water tank, is \(400 . \mathrm{kg} .\) The water can be directed, by switching a valve, either backward or forward. In both directions, the pressure washer ejects \(200 .\) L of water per min with a muzzle velocity of \(25.0 \mathrm{~m} / \mathrm{s}\). a) If the cart starts from rest, after what time should the valve be switched from backward (forward thrust) to forward (backward thrust) for the cart to end up at rest? b) What is the mass of the cart at that time, and what is its velocity? (Hint: It is safe to neglect the decrease in mass due to the gas consumption of the gas-powered pressure washer!) c) What is the thrust of this "rocket"? d) What is the acceleration of the cart immediately before the valve is switched?

Suppose you place an old-fashioned hourglass, with sand in the bottom, on a very sensitive analytical balance to determine its mass. You then turn it over (handling it with very clean gloves) and place it back on the balance. You want to predict whether the reading on the balance will be less than, greater than, or the same as before. What do you need to calculate to answer this question? Explain carefully what should be calculated and what the results would imply. You do not need to attempt the calculation.

Is it possible for two masses to undergo a collision such that the system of two masses has more kinetic energy than the two separate masses had? Explain.

A catapult on a level field tosses a 3 -kg stone a horizontal distance of \(100 \mathrm{~m}\). A second 3 -kg stone tossed in an identical fashion breaks apart in the air into 2 pieces, one with a mass of \(1 \mathrm{~kg}\) and one with a mass of \(2 \mathrm{~kg} .\) Both of the pieces hit the ground at the same time. If the 1 -kg piece lands a distance of \(180 \mathrm{~m}\) away from the catapult, how far away from the catapult does the 2 -kg piece land? Ignore air resistance. a) \(20 \mathrm{~m}\) c) \(100 \mathrm{~m}\) e) \(180 \mathrm{~m}\) b) \(60 \mathrm{~m}\) d) \(120 \mathrm{~m}\)

Find the location of the center of mass for a onedimensional rod of length \(L\) and of linear density \(\lambda(x)=c x\), where \(c\) is a constant. (Hint: You will need to calculate the mass in terms of \(c\) and \(L\).)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free