In an electric trolley or bus system, the vehicle motor draws current from an overhead wire by means of a long arm with an attachment at the end that slides along the overhead wire. A brilliant electric spark is often seen when the attachment crosses a junction in the wires where contact is momentarily lost. Explain this phenomenon.

Short Answer

Expert verified

Answer

The insulation property of air breaks down due to presence of high back electromotive force (voltage) which induces when contactis momentarily lost, causing brilliant electric spark.

Step by step solution

01

State Faraday’s law of induction and define insulation breakdown of air

Whenever a conductor is placed in a varying magnetic field, an electromotive force is induced. Magnetic field can be varying by changing current with time which leads to time rate of magnetic flux .

ε=dϕBdt

whereεdIdt is emf induced and dIdtis time rate of current.

Insulation breakdown of material is the phenomenon when the insulating material fails to prevent flow of current through it under high voltage. The voltage at which breakdown of insulation property of material starts to happen, is called breakdown voltage. When the voltage applied across the material is greater than breakdown voltage, material become conducting, losing its insulation.

When the insulating material is air and voltage is higher than breakdown voltage of air then air loses its insulating property and converts into conducting material by ionizing itself called plasma which appears as electric spark.

02

Apply Faraday’s law of induction

The vehicle motor draws current from an overhead wire by means of a long arm with an attachment at the end that slides along the overhead wire. When this overhead wire momentarily loses contact with the long arm, current in the conducting arm reduces from larger value to zero in very short period of time. This leads to time rate of current having high value that is high rate of flux.

Now according to Faraday’s law, high rate of current or flux leads to induction of high back emf which is opposite to supply voltage. This back emf is so strong that it breaks the insulation property of air between overhead wire and vehicle arm, causing air to go through the insulation breakdown which leads to electric spark.

Thus, when contact is momentarily lost,the insulation property of air breaks down due to induction of high back electromotive force (voltage) causing brilliant electric spark.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two coils have mutual inductance M=3.25×10-4H. The current in the first coil increases at a uniform rate of 830 A/S. (a) what is the magnitude of the induced emf in the second coil? Is it constant? (b) Suppose that the current described is in the second coil rather than the first. What is the magnitude of the induced emf in the first coil?

A 1.50- μF capacitor is charging through a 12.0-Ω resistor using a 10.0-V battery. What will be the current when the capacitor has acquired14of its maximum charge? Will it be14of the maximum current?

BIO Transmission of Nerve Impulses. Nerve cells transmit electric

signals through their long tubular axons. These signals propagate due to a

sudden rush of Na+ions, each with charge +e, into the axon. Measurements

have revealed that typically about 5.6×1011Na+ions enter each meter of the

axon during a time of . What is the current during this inflow of charge

in a meter of axon?

A light bulb glows because it has resistance. The brightness of a light bulb increases with the electrical power dissipated in the bulb. (a) In the circuit shown in Fig. Q25.14a, the two bulbs A and B are identical. Compared to bulb A, does bulb B glow more brightly, just as brightly, or less brightly? Explain your reasoning. (b) Bulb B is removed from the circuit and the circuit is completed as shown in Fig. Q25.14b. Compared to the brightness of bulb A in Fig. Q25.14a, does bulb A now glow more brightly, just as brightly, or less brightly? Explain your reasoning

In the circuit shown in Fig. E26.49, C = 5.90 mF, Ԑ = 28.0 V, and the emf has negligible resistance. Initially, the capacitor is uncharged and the switch S is in position 1. The switch is then moved to position 2 so that the capacitor begins to charge. (a) What will be the charge on the capacitor a long time after S is moved to position 2? (b) After S has been in position 2 for 3.00 ms, the charge on the capacitor is measured to be 110 mC What is the value of the resistance R? (c) How long after S is moved to position 2 will the charge on the capacitor be equal to 99.0% of the final value found in part (a)?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free