The potential difference between the two terminals of an AA battery (used in flashlights and portable stereos) is 1.5 V. If two AA batteries are placed end to end with the positive terminal of one battery touching the negative terminal of the other, what is the potential difference between the terminals at the exposed ends of the combination? What if the two positive terminals are touching each other? Explain your reasoning.

The electric potential difference between points A and B, VB−VA is defined to be the change in potential energy of a charge q moved from A to B, divided by the charge. Units of potential difference are joules per coulomb, given the name volt (V) after Alessandro Volta.

Solution:

As we know the potential difference between the two batteries gives kinetic energy to the electrons to enable them to now.

Also, we know that the electrons move for the high potential plate to the low potential plate- If the two batteries placed end

to end with the negative terminal to the positive terminal, then the total potential difference is 3 V. If the two batteries

placed end to end with the positive terminal to the positive terminal, then the total potential difference is 0 V- In this case,

we get an equilibrium between the two batteries- 80, there are not electrons flow occurring-

Therefore ,

If the two batteries placed end to end with the negative terminal to the positive terminal, then the total potential difference is 3 V-

If the two batteries placed end to end with the positive terminal to the positive terminal, then the total potential difference is 0 V-

In this case, we get an equilibrium betWeen the two batteries- so, there are not electrons flow occurring-