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Chapter 4: Q10E (page 1044)

A Radio Inductor. You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.80 mA when a sinusoidal voltage with amplitude 12.0 V is applied across the inductor. What frequency is required?

Short Answer

Expert verified

The required frequency of the ac source is 2.36 MHz.

Step by step solution

01

Given Data

An inductor is a passive two-terminal device that stores energy in a magnetic field when current passes through it.

The amplitude of voltage, V = 12.0 V

The amplitude of current, I = 1.80 mA

The inductance of the coil, L = 0.450 mH

02

Determination of frequency

Equation for voltage across the inductor –

VL=1ωLVL=I2πfLf=VL2πILf=12.0V2π1.80*10-3A*0.450*10-3Hf=2.36*106Hz

Therefore, the required frequency of the ac source is 2.36 Mega-Hertz.

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