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Chapter 4: Q11E (page 746)

A6.20μC point charge is at the center of a cube with sides of length 0.500m. (a) What is the electric flux through one of the six faces of the cube? (b) How would your answer to part (a) change if the sides long 0.250m? Explain.

Short Answer

Expert verified

(a) The electric flux through one of the six faces of the cube is FE=1.17×105N.m2/C.

(b) No change in electric flux.

Step by step solution

01

Definition of electric flux

The term electric flux may be defined as the application of electric field that may be thought of as the number of electric lines of force that intersect a given area.

02

Determine the electric flux

The electric flux can be calculated by the relation

FE=Qenclε0

WhereQencl,ε0 total charged enclosed and electric constant respectively.

FE=6.20×10-6C8.85×10-12C2/N.m2FE=7.00×105N.m2/C

And the electric flux from one side is calculated as

FE=167.00×105N.m2/CFE=1.17×105N.m2/C

Hence, the electric flux through one of the six faces of the cube is FE=1.17×105N.m2/C.

Now the size of the cube change by the length 0.250m There is no any change in electric flux because it calculated by the charge enclosed in it.

Hence, no change in electric flux.

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