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Chapter 4: Q11E (page 809)

A spherical capacitor contains a charge of 3.30 nC when connected to a potential difference of 220 V. If its plates are separated by vacuum and the inner radius of the outer shell is 4.00 cm, calculate:

(a) the capacitance

(b) the radius of the inner sphere;

(c) the electric field just outside the surface of the inner sphere.

Short Answer

Expert verified

The capacitance is 15.0 pF

The radius of the inner sphere is 3.0cm.

The electric field according to gauss law is3.3×104N/C

Step by step solution

01

Step 1:

Given rb=4.0cm,V=220V,Q=3.3nC.

The capacitance is given by

Hence the capacitance is 15.0pF

02

Step 2:

Hence the capacitance is given by

Simplify equation(1)


Simplify above equation


Hence the radius of the inner sphere is 3.0cm.

03

Step 3:

The electric field according to gauss law


Substitute in equation(3)


Therefore the electric field according to gauss law is3.3×104N/C

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