An open plastic soda bottle with an opening diameter of 2.5cmis placed on a table. A uniform 1.75-Tmagnetic field directed upward and oriented25° from the vertical encompasses the bottle. What is the total magnetic flux through the plastic of the soda bottle?

Short Answer

Expert verified

The total magnetic flux through the plastic of the soda bottle is-7.79×10-4Wb

Step by step solution

01

Definition of magnetic flux

The term magnetic flux may be defined as the measurement of total magnetic field passing through the given area.

02

Determine the total magnetic flux through the plastic bottle

The sum of magnetic flux through the plastic and through the open cap is net magnetic flux through the bottle.

fnet=fplastic+fcapfnet=ofplastic+fcap=ofplastic=-fcap

Now

fplastic=-BAcosθfplastic=-Bπr2cosθfplastic=-πr2Bcosθ

Here B,A,rand θare magnetic field, area of open cap, radius and angle between magnetic field and the area vector respectively.

Put all the given values andr=d/2

fplastic=-π1.25×10-2m21.75Tcos25°fplastic=-7.79×10-4Wb

Hence, the total magnetic flux through the plastic of the soda bottle is -7.79×10-4Wb

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two copper wires with different diameter are joined end to end. If a current flow in the wire combination, what happens to electrons when they move from the large diameter wire into the smaller diameter wire? Does their drift speed increase, decrease, or stay the same? If the drift speed change, what is the role the force that causes the change? Explain your reasoning.

An 18-gauge copper wire (diameter 1.02 mm) carries a current

with a current density of 3.2×106Am2. The density of free electrons for

copper is8.5×1028electrons per cubic meter. Calculate (a) the current in

the wire and (b) the drift velocity of electrons in the wire.

The heating element of an electric dryer is rated at 4.1 kW when connected to a 240-V line. (a) What is the current in the heating element? Is 12-gauge wire large enough to supply this current? (b) What is the resistance of the dryer’s heating element at its operating temperature? (c) At 11 cents per kWh, how much does it cost per hour to operate the dryer?

A circular area with a radius of6.50cmlies in the xy-plane. What is the magnitude of the magnetic flux through this circle due to a uniform magnetic fieldlocalid="1655727900569" B=0.230T(a) in the direction of +z direction; (b) at an angle of53.1°from the direction; (c) in the direction?

In the circuit shown in Fig. E26.49, C = 5.90 mF, Ԑ = 28.0 V, and the emf has negligible resistance. Initially, the capacitor is uncharged and the switch S is in position 1. The switch is then moved to position 2 so that the capacitor begins to charge. (a) What will be the charge on the capacitor a long time after S is moved to position 2? (b) After S has been in position 2 for 3.00 ms, the charge on the capacitor is measured to be 110 mC What is the value of the resistance R? (c) How long after S is moved to position 2 will the charge on the capacitor be equal to 99.0% of the final value found in part (a)?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free