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Chapter 4: Q15E (page 714)

In Example 21.3, calculate the net force on chargeq1

Short Answer

Expert verified

The net force on the charge q1is 18.0×10-5N.

Step by step solution

01

Step 1:

As q2exerting an attractive force on charge q1

And q3exerting a repulsive force in charge q1.

So, combining the two forces to find the net force exerted on q1.

02

Step 2:

Force by q2on q1is

F2=kq1q2r2

Here, K is 9.0×109N·m2/C2, r is the distance between q1and q2, r=2cm

q1=1.0nCand q2=3.0nC

Putting all these values

F2=9.0×109-3×10-91×10-90.022=6.75×10-5N

03

Step 3:

Force by q3on q1is

F3=Kq3q1r2

Here, q1=1.0nCandq3=5.0nC

Putting all these values

F3=9.0×1095×10-91×10-90.022=11.25×10-5N

So, the net force is

Fnet=F2+F3=6.75×10-9+11.25×10-9=18.0×10-5N

Hence, the Net force on the chargeq1 is 18.0×10-5N .

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Most popular questions from this chapter

(See Discussion Question Q25.14.) An ideal ammeter A is placed in a circuit with a battery and a light bulb as shown in Fig. Q25.15a, and the ammeter reading is noted. The circuit is then reconnected as in Fig. Q25.15b, so that the positions of the ammeter and light bulb are reversed. (a) How does the ammeter reading in the situation shown in Fig. Q25.15a compare to the reading in the situation shown in Fig. Q25.15b? Explain your reasoning. (b) In which situation does the light bulb glow more brightly? Explain your reasoning.

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