In terms of the dielectric constant K, what happens to The electric flux through the Gaussian surface shown in Fig. 24.22 When the dielectric is inserted into the previously empty space Between the plates? Explain.

Short Answer

Expert verified

The electric flux will decrease as a dielectric is inserted between the two plates

Step by step solution

01

Step 1:About The  Gaussian Surface

Gaussian surface (sometimes abbreviated as G.S.) is a closed surface in three-dimensional space through which the flux of a vector field is calculated; usually the gravitational field, the electric field, or magnetic field.

02

Determine When the dielectric is inserted into the previously empty space Between the plates

A shown by equation 24.23

The electric field is inversely proportional to the dielectric constant K, as the dielectric constant increases the electric field decreases, therefore, the electric flux will decrease as a dielectric is inserted between the two plates

Result

Therefore The electric flux will decrease as a dielectric is inserted between the two plates

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

High-voltage power supplies are sometimes designed intentionally to have rather large internal resistance as a safety precaution. Why is such a power supply with a large internal resistance safer than a supply with the same voltage but lower internal resistance?

A particle with mass1.81×10-3kgand a charge of has1.22×10-8C, at a given instant, a velocityV=(3.00×104m/s).What are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic fieldB=(1.63T)i+(0.980T)j^?

Each of the lettered points at the corners of the cube in Fig. Q27.12 represents a positive charge qmoving with a velocity of magnitude vin the direction indicated. The region in the figure is in a uniform magnetic field , parallel to the x-axis and directed toward the right. Which charges experience a force due to B? What is the direction of the force on each charge?

A fuse is a device designed to break a circuit, usually by melting when the current exceeds a certain value. What characteristics should the material of the fuse have?

Light Bulbs in Series and in Parallel. Two light bulbs have constant resistances of 400Ωand 800Ω. If the two light bulbs are connected in series across a 120Vline, find (a) the current through each bulb; (b) the power dissipated in each bulb; (c) the total power dissipated in both bulbs. The two light bulbs are now connected in parallel across the120Vline. Find (d) the current through each bulb; (e) the power dissipated in each bulb; (f) the total power dissipated in both bulbs. (g) In each situation, which of the two bulbs glows the brightest? (h) In which situation is there a greater total light output from both bulbs combined?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free