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Chapter 4: Q20E (page 1014)

It has been proposed to use large inductors as energy storage devices. (a) How much electrical energy is converted to light and thermal energy by a150Wlight bulb in one day? (b) If the amount of energy calculated in part (a) is stored in an inductor in which the current is80A, what is the inductance?

Short Answer

Expert verified

a) U=1.296×107J

b)L=4.05×103H

Step by step solution

01

Formulas used in the given problem

The energy stored in the inductor is given by U=12LI2.

The power and time period are also given whose product will give us the energy. Use the formula of energy to calculate the self-inductance.

02

Calculate the self-inductance

Given that P=150W,I=80Aand t=24h. The energy is given by

U=PtU=150×24×3600U=1.296×107J

Use the value of energy to find the self-inductance

localid="1664179296238" L=2UI2L=2×1.296×107802L=4.05×103H

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