Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Q20E (page 842)

You apply a potential difference of 4.50 Vbetween the ends of a wire that is 2.50 m in length and 0.654 mm in radius. The resulting current through the wire is 17.6 A. What is the resistivity of the wire?

Short Answer

Expert verified

The resistivity of the wire is13.8×10-8Ωm .

Step by step solution

01

Determine the area of the wire

The given data is:

V=4.50V,L=2.50,m=0.654mm,andl=17.6A

Now, the area of the wire can be calculated as:

A=πr2A=π×0.654×10-32A=1.344×10-6m2

02

Determine the resistance of the wire

Now,

R=VIR=4.5017.6R=0.256Ω

Thus, the resistance of the wire is 0.256Ω

03

Determine the resistivity of the wire

The formula to find resistivity is:

ρ=RAL

Substitute the given values

ρ=0.256Ω1.344×10-6m22.50mρ=13.8×10-8Ωm

Therefore, the resistivity of the wire is 13.8×10-8Ωm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An 18-gauge copper wire (diameter 1.02 mm) carries a current

with a current density of 3.2×106Am2. The density of free electrons for

copper is8.5×1028electrons per cubic meter. Calculate (a) the current in

the wire and (b) the drift velocity of electrons in the wire.

Question: A positive point charge is placed near a very large conducting plane. A professor of physics asserted that the field caused by this configuration is the same as would be obtained by removing the plane and placing a negative point charge of equal magnitude in the mirror image position behind the initial position of the plane. Is this correct? Why or why not?

When a resistor with resistance Ris connected to a 1.50-V flashlight battery, the resistor consumes 0.0625 W of electrical power. (Throughout, assume that each battery has negligible internal resistance.) (a) What power does the resistor consume if it is connected to a 12.6-V car battery? Assume that Rremains constant when the power consumption changes. (b) The resistor is connected to a battery and consumes 5.00 W. What is the voltage of this battery?

Current passes through a solution of sodium chloride. In

1.00s,2.68×1016Na+ions arrive at the negative electrode and3.92×1016CI-

ions arrive at the positive electrode. (a) What is the current passing between

the electrodes? (b) What is the direction of the current?

A25.0-Ωbulb is connected across the terminals of a12.0-Vbattery having3.50Ωof internal resistance. What percentage of the power of the battery is dissipated across the internal resistance and hence is not available to the bulb?

See all solutions

Recommended explanations on Physics Textbooks

Particle Model of Matter

Read Explanation

Modern Physics

Read Explanation

Classical Mechanics

Read Explanation

Oscillations

Read Explanation

Torque and Rotational Motion

Read Explanation

Rotational Dynamics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free