Question: A hollow aluminum cylinder is 2.50 mlong and has an inner radius of 2.75 cmand an outer radius of 4.60 cm. Treat each surface (inner, outer, and the two end faces) as an equipotential surface. At room temperature, what will an ohmmeter read if it is connected between (a) the opposite faces and (b) the inner and outer surfaces?

Short Answer

Expert verified
  1. The ohmmeter read if it is connected between the opposite faces isR=1.61x10-5Ω
  2. The ohmmeter read if it is connected between the inner and outer surfaces isR=9.01x10-10Ω

Step by step solution

01

Determine the ohmmeter read if it is connected between the opposite faces

a. The cross-sectional area of the cylinder is

Now, we know the formula

R=ρLA

Substitute the given values

Therefore, the ohmmeter reading if the ohmmeter is connected between the opposite faces is

02

Determine the formula to find the ohmmeter reading if it is connected between the inner and outer surfaces

b. The current flows radially inward or outward (which depends on the direction of the current) when the ohmmeter is connected between the inner and outer surfaces.

Let us assume a thin cylindrical shell of length L, radius r, and thickness dr(the outer radius is approximately equal to inner radius)

We know, the current moves radially, so, the current moves along a distance L = dr and through a cross-sectional area .

Now, the resistance of this conductor is

The current that flows radially from , the resistance is

03

Determine the ohmmeter reading when it is placed between the inner and outer surfaces

Use the formula found above,

R=ρ2πLlnroutrin

Substitute the given values

Therefore, when the ohmmeter is placed between the inner and outer surfaces, the ohmmeter reading is found to be

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Most popular questions from this chapter

A rule of thumb used to determine the internal resistance of a source is that it is the open circuit voltage divide by the short circuit current. Is this correct? Why or why not?

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