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Chapter 4: Q29E (page 1014)

In Fig. 30.11switchS1is closed while switch S2is kept open. The inductance is L=0.38H, the resistance is R=48Ω, and the emf of the battery is 18V. At time tafter s1is closed, the current in the circuit is increasing at a rate of didt=7.2A/s. At this instant what is vab, the voltage across the resistor?

Short Answer

Expert verified

Voltage across the resistance is 15.3V.

Step by step solution

01

Calculate the voltage across the resistance

Consider the following circuit where L=0.38H,R=48Ωand ε=18V.


It is given that the switch s1is closed while the switch S2is kept open. At a certain instant the current is increasing at a rate of didt=7.2A/s, we need to find the voltage across the resistor at this instant. To find the potential, we apply the Kirchhoff’s loop rule to the upper loop, so we get,

ε-vR-vL=0

But,vL=Ldidt

So, localid="1664178496830" ε-vR-Ldidt=0

Solve for and substitute to get,

So, voltage across the resistance is 15.3V.

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