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Chapter 4: Q31E (page 715)

In Exercise 21.29, what is the speed of the electron as it emerges from the field?

Short Answer

Expert verified

Speed of electron is v=1.79×106m/s.

Step by step solution

01

Step 1:

As the velocity vector is made up of two components x and y.

Therefore,vx=1.6×106m/s

As no acceleration is along x-direction, the velocity remains unchanged from initial velocity.

As the particle has no initial velocity sovy0=0

vy=vy0+atvy=at=E0qmt=364×1.6×10−199.1×10−31×1.25×10−8=8×105m/s

02

Step 2:

|v→|=vx2+vy2=1.6×1062+8×1052≈1.79×106m/s

Hence, Speed of electron isv=1.79×106m/s.

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