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Chapter 4: Q46E (page 950)

A 15.0-cm-long solenoid with radius 0.750 cm is closely wound with 600 turns of wire. The current in the windings is 8.00 A. Compute the magnetic field at a point near the centre of the solenoid.

Short Answer

Expert verified

The magnetic field at the center of the solenoid is 0.0402T

Step by step solution

01

Concept of the magnetic field at the center of the solenoid

The magnetic field at the center of the solenoid is given by,Bsolenoid=μ0nlwheren=NLthus,Bsolenoid=μ0NLI were where,μ0=4π×10−7H/mis permeability of free space, N is the number of turns, I is the current passing through the coil

02

Find the magnetic field at the center of the solenoid

Consider a solenoid which is L= 15.0 cm long and contains N =600 circular coils R =0.750 cm in radius, it carries a current of I= 8.00 A. The magnetic field at the center of the solenoid is given by,Bsolenoid=μ0NL Substitute the values in the given equation we have,

Bsolenoid=4π×10−7Tm/A6000.15(8.00A)=0.0402T

Therefore, the magnetic field at the center of the solenoid is 0.0402T

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