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Chapter 4: Q48E (page 716)

A point charge is at the point , and a second point charge is at the point . Calculate the magnitude and direction of the net electric field at the origin due to these two point charges.

Short Answer

Expert verified

Magnitude of the electric field is

The Direction of electric field is in negative direction of x with an angle

Step by step solution

01

About Electric field Magnitude and direction 

Electric field can be considered as an electric property associated with each point in the space where a charge is present in any form. An electric field is also described as the electric force per unit charge.

02

Step 2:Determine the magnitude and direction of the net electric field at the originAs given

Solve for Electric force of each cahrge

we have two electric field so for first

now solve for second

Now solve for Net electricfield

Therefore , Magnitude of the electric field is

03

Determine the Direction of electric field  

Solve for direction

Therefore the Direction of electric field is in negative direction of x with an angle.

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Most popular questions from this chapter

In the circuit shown in Fig. E25.30, the 16.0-V battery is removed and reinserted with the opposite polarity, so that its negative terminal is now next to point a. Find (a) the current in the circuit (magnitude anddirection); (b) the terminal voltage Vbaof the 16.0-V battery; (c) the potential difference Vacof point awith respect to point c. (d) Graph the potential rises and drops in this circuit (see Fig. 25.20).

In the circuit of Fig. E25.30, the 5.0 Ω resistor is removed and replaced by a resistor of unknown resistance R. When this is done, an ideal voltmeter connected across the points band creads 1.9 V. Find (a) the current in the circuit and (b) the resistance R. (c) Graph the potential rises and drops in this circuit (see Fig. 25.20).

The current in a wire varies with time according to the relationship

I=55A-(0.65As2)t2. (a) How many coulombs of charge pass a cross section of the wire in

the time interval between t=0and role="math" localid="1655721302619" t=8.0s? (b) What constant current would transport the

same charge in the same time interval?

When switch Sin Fig. E25.29 is open, the voltmeter V reads 3.08 V. When the switch is closed, the voltmeter reading drops to 2.97 V, and the ammeter A reads 1.65 A. Find the emf, the internal resistance of the battery, and the circuit resistance R. Assume that the two meters are ideal, so they don’t affect the circuit.

Fig. E25.29.

In the circuit shown in Fig. E26.20, the rate at which R1 is dissipating electrical energy is 15.0 W. (a) Find R1 and R2. (b) What is the emf of the battery? (c) Find the current through both R2 and the 10.0 Ω resistor. (d) Calculate the total electrical power consumption in all the resistors and the electrical power delivered by the battery. Show that your results are consistent with conservation of energy.
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