An 18-gauge copper wire (diameter 1.02 mm) carries a current

with a current density of 3.2×106Am2. The density of free electrons for

copper is8.5×1028electrons per cubic meter. Calculate (a) the current in

the wire and (b) the drift velocity of electrons in the wire.

Short Answer

Expert verified

a) The current in the wire is /=2.61A.

b) The drift velocity of the electrons in the wire is Vd=2.353×10-4ms

Step by step solution

01

Formula of current and velocity drift.

Consider the area of cross section is

A=πd24

Here, dis the diameter.

Consider the expression for the current is:

Vd=Jnqπd24 ….. (1)

Here, nis the charge concentration and q is the charge.

Consider the expression for the current density:

J=IAI=JA

Rewrite as:

I=Jπd24 …… (2)

02

Determine the value for the current.

(a)

Given is the density of current in the wire as 3.2×106Am2

Diameter of the wire as 1.02×10-3m

Substitute the values in the equation (2) and solve as,

I=3.2×106Am2π1.02×10-3m24=2.61A

03

Calculation of velocity drift.

(b)

Given the number of electrons as 8.5×1028and the charge of a electron is

1.6×10-19coulombs.

Substitute the values in the equation (1) and solve as,

Vd=3.2×106Am28.5×1028×1.6×10-19=2.353×10-4ms

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