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Chapter 4: Q51P (page 1016)

An Electromagnetic Car Alarm. Your latest invention is a car alarm that produces sound at a particularly annoying frequency of 3500 Hz. To do this, the car-alarm circuitry must produce an alternating electric current of the same frequency. That’s why your design includes an inductor and a capacitor in series. The maximum voltage across the capacitor is to be 12.0V . To produce a sufficiently loud sound, the capacitor must store 0.0160 J of energy. What values of capacitance and inductance should you choose for your car-alarm circuit?

Short Answer

Expert verified

A) The value of capacitance is222μF

B) The value of inductance is9.31μH

Step by step solution

01

Concept of the energy in the capacitor

The energy in capacitor is Uc=12CV2where, C is the capacitance and V is the voltage

02

Calculate the values of capacitance

From the given value of the stored energy Uc in the capacitor, we can calculate the capacitance C

C=2UcV2=20.016J12V2=222×10-6F=222μF

Therefore, the value of capacitance is222μF

03

Calculate the values of inductance

For the self-inductance, we use the given value of frequency f from equation in the formL=12πf2C.Substitute the values in the given equation we get,

L=12π3500Hz2222μF=9.31μH

Therefore, the value of inductance is9.31μH

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Most popular questions from this chapter

CALC The region between two concentric conducting spheres with radii and is filled with a conducting material with resistivity ρ. (a) Show that the resistance between the spheres is given by

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