Chapter 4: Q5E (page 912)

An electron experiences a magnetic force of magnitude $4.60 \times 10^{- 15} N$ when moving at an angle of 60.0° with respect toa magnetic field of magnitude $3.50 \times 10^{- 3} T$ . Find the speed ofthe electron.

Short Answer

Expert verified

The velocity is $\overset{⇀}{v} = 9.49 \times 10^{6} m / s$

Step by step solution

The significance of the magnetic field

The magnetic field force is given by
$F_{B} = q (v \times B) F = qvBsinθ$

Where q is the charge of the particle, V is the velocity and B is the magnetic field

Determination of the speed of the electron

We know that the magnetic field force is given by

$F = q (v \times B) F = q |v| |B| \sin θ$

Rearranging we get

$|V| \frac{F}{q |B| s i n θ}$

Plug the values

$V = \frac{4.60 \times 10^{- 15} N}{(1.6 \times 10^{- 19} C) (3.50 \times 10^{- 3} T) s i n 60} v = 9 . 49^{6} m / s Hence, the velocity is \overset{⇀}{v} = 9.49 \times 10^{6} m / s$

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An electron experiences a magnetic force of magnitude $4.60 \times 10^{- 15} N$ when moving at an angle of 60.0° with respect toa magnetic field of magnitude $3.50 \times 10^{- 3} T$ . Find the speed ofthe electron.

Short Answer

Step by step solution

The significance of the magnetic field

Determination of the speed of the electron

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An electron experiences a magnetic force of magnitude4.60×10-15Nwhen moving at an angle of 60.0° with respect toa magnetic field of magnitude3.50×10-3T. Find the speed ofthe electron.

Short Answer

Step by step solution

The significance of the magnetic field

Determination of the speed of the electron

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Magnetism and Electromagnetic Induction

Measurements

Electromagnetism

Further Mechanics and Thermal Physics

Electricity and Magnetism

Wave Optics

Study anywhere. Anytime. Across all devices.

An electron experiences a magnetic force of magnitude $4.60 \times 10^{- 15} N$ when moving at an angle of 60.0° with respect toa magnetic field of magnitude $3.50 \times 10^{- 3} T$ . Find the speed ofthe electron.