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Chapter 4: Q60P (page 813)

Each combination of capacitors between points a and b in Fig. P24.60 is first connected across a 120V battery, charging the combination to 120 V. These combinations are then connected to make the circuits shown. When the switch S is thrown, a surge of charge for the discharging capacitors flows to trigger the signal device. How much charge flows through the signal device in each case?

Short Answer

Expert verified

QP=7.2×10-3CQS=6.54×10-4C

Step by step solution

01

Parameters.

C1=10μFC2=20μFC3=30μFVab=210V

02

Computing the charge flow through the signal device in each case.

In parallel system the total capacitance is given by

C1+C2+C3=10+20+30=60μF

The charge stored in the system is given by

Qt=CtVt=120×60×10-6=7.2×10-3C

In series system the total capacitance is given by

1Ct=1C3+1C2+1C1=110+120+130=6011

The charge stored in the system is given by

Qs=CtVt=120×4.45×10-6=6.54×10-4C

Therefore the total charge flow in each case is

QP=7.2×10-3CQS=6.54×10-4C.

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