Two spherical shells have a common center. The inner shell has radiusR1= 5.00 cm and chargeq1=+3.0×10-6C; the outer shell has radius R2= 15.0 cm and chargelocalid="1664267292506" q2=-5.0×10-6C. Both charges are spread uniformly over the shell surface. What is the electric potential due to the two shells at the following distances from their common center: (a) r = 2.50 cm; (b) r = 10.0 cm; (c) r = 20.0 cm? Take V = 0 at a large distance from the shells.

Short Answer

Expert verified
  1. V = 240kV
  2. V = -30kV
  3. V = -90kV

Step by step solution

01

Step 1:

Given data:

Potential inside the sphere (r<R) where (R) is the radius of the sphere and the potential is constant


And if (r) is the distance, then the potential is;


02

Step 2:

At r=2.50cm=0.025m,

The total potential is the sum of the potential of two spheres for the first sphere r<R1and for the second sphere is r<R2.

Therefore, the equation is:

03

Step 3:

At r=10.0cm=0.10m

The total potential is the sum of the potential of two spheres for the first sphere r>R1and for the second sphere is r<R2.

Therefore, the equation is:

04

Step 4:

At r=20.0cm=0.20m

The total potential is the sum of the potential of two spheres for the first sphere r>R1and for the second sphere is r>R2.

Therefore, the equation is:

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