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Chapter 4: Q64P (page 781)

Deflecting Plates of an Oscilloscope. The vertical deflecting plates of a typical classroom oscilloscope are a pair of parallel square metal plates carrying equal but opposite charges. Typical dimensions are about 3.0 cm on a side, with a separation of about 5.0 mm. The potential difference between the plates is 25.0 V. The plates are close enough that we can ignore fringing at the ends. Under these conditions: (a) how much charge is on each plate, and (b) how strong is the electric field between the plates? (c) If an electron is ejected at rest from the negative plate, how fast is it moving when it reaches the positive plate?

Short Answer

Expert verified

(a) Charge on a plate isQ=3.98×10-11C

(b) Electric field between the plates isE=5.0×103N/C

(c) Speed of electron is2.97×106m/s

Step by step solution

01

Step 1:

Given data:

V=25.0Vd=5.0mmL=W=3.0cm

(a) Here the electric field is

V=Ed⇒E=Vd

So electric field is

E=σ∈0=QA∈o

Further solving

Vd=QA∈o

Putting the values;

Hence, the charge on a plate is .

02

Step 2:

(b) Electric field between plates is;

Therefore, the electric field between the plates is .

03

Step 3:

(c) Electric force due to electric field is

Putting all the values therefore the value of acceleration is

Now the velocity is

Putting all the values

Hence when it reaches the positive plate speed of the electron is .

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