Two protons, starting several meters apart, are aimed directly at each other with speeds of 2.00×105ms, measured relative to the earth. Find the maximum electric force that these protons will exert on each other.

Short Answer

Expert verified

The maximum electric force is0.194×10-4N that these protons will exert on each other.

Step by step solution

01

Electric force

The electric force between two protons is as follows:

F=14ττε0|q1q2|rb2

The electric force acting of protons is derived as follows:

role="math" localid="1664256985484" F=14πε0|q1q2|rb2

F=14ττε0|q1q2|rb2

Here,role="math" localid="1664256998618" 14πε0×9×109N.m2C2

02

Determine the value of electric force

Consider the charge of the proton is 1.602×10-19C.

Consider the total kinetic energy for those two particles are equal.

212mv2=14πε0e2rbrb=14πε0e2mv2

Substitute the values and solve as:

rb=9×109N.m2C21.602×10-19C21.67×10-27kg2×105ms2=3.45×10-12m,

Solve for the maximum force as:

F=14πε0e2rb2=9×109N.m2C21.607×10-19C23.45×10-12m2=0.194×10-4N

Therefore, the maximum electric force is0.194×10-4N that these protons will exert on each other.

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