Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Q9E (page 809)

A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 10.0 pC. The inner cylinder has a radius of 0.50 mm, the outer one has a radius of 5.00 mm, and the length of each cylinder is 18.0 cm. (a) What is the capacitance? (b) What applied potential difference is necessary to produce these charges on the cylinders?

Short Answer

Expert verified

The Capacitance is 4.35×10-12F.

The electric voltage required to keep this charge is given by 2.3V.

Step by step solution

01

Step 1:

Given Q=10×10-12C,ra=0.5mm,ra=0.5×10-3m,L=180cm

The capacitance of the coaxial cylinder according is given

Substitute in equation(1)


The electric voltage required to keep this charge is given by

02

Step 2:

The Capacitance is4.35×10-12F.

The electric voltage required to keep this charge is given by 2.3V.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the circuit of Fig. E25.30, the 5.0 Ω resistor is removed and replaced by a resistor of unknown resistance R. When this is done, an ideal voltmeter connected across the points band creads 1.9 V. Find (a) the current in the circuit and (b) the resistance R. (c) Graph the potential rises and drops in this circuit (see Fig. 25.20).

A particle with mass1.81×10-3kgand a charge of has1.22×10-8C, at a given instant, a velocityV⇀=(3.00×104m/s).What are the magnitude and direction of the particle’s acceleration produced by a uniform magnetic fieldB=(1.63T)i+(0.980T)j^?

Can potential difference between the terminals of a battery ever be opposite in direction to the emf? If it can, give an example. If it cannot, explain why not.

An emf source with E = 120 V, a resistor with R = 80.0 Ω, and a capacitor with C = 4.00 µF are connected in series. As the capacitor charges, when the current in the resistor is 0.900 A, what is the magnitude of the charge on each plate of the capacitor?

A 1.50- μF capacitor is charging through a 12.0-Ω resistor using a 10.0-V battery. What will be the current when the capacitor has acquired14of its maximum charge? Will it be14of the maximum current?
See all solutions

Recommended explanations on Physics Textbooks

Magnetism

Read Explanation

Fluids

Read Explanation

Physics of Motion

Read Explanation

Geometrical and Physical Optics

Read Explanation

Measurements

Read Explanation

Astrophysics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free