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Chapter 1: Q11-27E (page 1)

A metal rod that is 4.00 m long and 0.50 cm2 in cross-sectional area is found to stretch 0.20 cm under a tension of 5000 N. What is Young’s modulus for this metal?

Short Answer

Expert verified

2×1011Pa

Step by step solution

01

Given information

Lengthl0=4.00m,AreaA=0.50cm2,Elongation∆I=0.20cm,TensionForcef=4000N

02

Concept/Formula used

Y=l0FAΔl

Where, Y is Young’s modulus, I0 is length of muscle, F is muscle force, A is cross-sectional area and ∆lis elongation.

03

Young’s modulus Calculation

Y=4.00m5000N0.50×10-4m20.20×10-2m=2×1011Pa

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