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Chapter 1: Q11-33E (page 360)

A specimen of oil having an initial volume of 600 cm3 is subjected to a pressure increase of 3.6*106Pa , and the volume is found to decrease by 0.45 cm3. What is the bulk modulus of the material? The compressibility?

Short Answer

Expert verified

4.8×109Pa2.1×1010Pa-1

Step by step solution

01

Given information:

V0=600cm3,Δp=3.6*106Pa,ΔV=-0.45cm3

02

Concept/Formula used:

Bulk modulus is given by the ratio of pressure applied to the corresponding relative decrease in the volume of the material.

Mathematically, it is represented as follows:

β=ΔpΔVV0

Where, βis Bulk modulus

ΔpIs change of the pressure or force applied per unit area on the material

ΔVis Change of the volume of the material due to the compression

V0is Initial volume of the material

03

Bulk modulus calculation

β=ΔpΔVV0=-3.6*106Pa600cm3-0.45cm3=4.8×109Pa

k=1β=14.8×109Pa=2.1×1010Pa-1

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