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Chapter 1: Q1E (page 58)

A car travels in the +x-direction on a straight and level road. For the first 4.00 s of its motion, the average velocity of the car is Vav-x=6.25m/s. How far does the car travel in 4.00 s?

Short Answer

Expert verified

The displacement done by the car in 4.00s is,s=25m 

Step by step solution

01

Average velocity

Average velocity is the ratio of the rate of displacement over time.

v=dt………………(i)

Where, v= average velocity, s= total displacement, t= time travel

02

Identification of the given data

The average velocity is,vav-x=6.25 m/s

Time interval is, t=4.00s

03

Calculation of the total displacement by the car

Thus,using equation (i), we can write the displacement caused by the car will be,

d=v×t

Substituting the given values in the above expression, the displacement will be,

d=6.25m/s×4.00s=25m

Thus, the total displacement by the car is=25m

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