What is the ratio of the gravitational pull of the sun on the moon to that of the earth on the moon? (Assume the distance of the moon from the sun can be approximated by the distance of the earth from the sun.) Use the data in Appendix F. Is it more accurate to say that the moon orbits the earth, or that the moon orbits the sun?

Short Answer

Expert verified

The ratio is 2.253

Step by step solution

01

Identification of the given data

The given data can be listed below as,

  • Gravitational Pull of Sun
  • Gravitational Pull of Moon
02

Significance of Newton’s Law of Gravitation

03

Determination of the ratio of the gravitational pull of sun on moon to that of earth on moon

The gravitational force of attraction given by the Newton’s law is given as,

F=GM1M2d2 …(i)

Here M1 is the mass of the object (1), M2 is the mass of the object (2), R1is the Radius of object (1), R2is the Radius of object (2), d is the distance between these two objects.

Let us consider the M1 and M2 as sun and moon respectively. The gravitational pull of sun on moon is given from equn (i) as,

Fs=GM1M2ds2

Let us consider the M1 and M2 as earth and moon respectively. The gravitational pull of sun on moon is given from equn (i) as,

Fe-m=GMeMmds2

Here Fs-mis the sun-moon, Fe-mis the force of earth-moon, Ms is the mass of sun, Mm is the mass of the moon, Me is the mass of the earth, ds is the distance of sun to moon, de is distance of earth to moon.

The ratio is given as of the gravitational pull,

Fs-m=GMsMmds2Fe-m=GMeMmds2

The common terms get cancelled each other and the above equation becomes,

Fs-m=Msds2Fe-m=Meds2Fs-mFe-m=Msds2*de2Me

By substituting the values for Ms, de, ds, Me from the Appendix,

Fs-mFe-m=1.99*10301.5*1082*3.9*10525.97*1024=30.2679*104013.4325*1040Fs-mFe-m=2.253

The ratio of the gravitational pull of the sun on the moon to that of the earth on the moon is 2.253

The moon moves around the earth in 27 days, both the earth and moon rotates the sun.

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