Let be the angle that the vectormakes with the +x-axis, measured counterclockwise from that axis. Find angle for a vector that has these components: (a) $A_x=2.00m,A_y=-1.00m$ ; (b$A_x=2.00m,A_y=1.00m$ ; (c) $A_x=-2.00m,A_y=1.00m$ ; (d) $A_x=-2.00m,A_y=-1.00m$

Here different coordinates of the vector are given. We are knowing that in coordinates $x$component of the vector will be first and then the $y$component. Now to find the angle of the vector with respect to the $x$-axis we just need to take the ratio of the $y$component to that of the $x$component and then take the tan inverse of that value.

This will give you the angle of the vector with the x-axis.

It can be represented as

$\theta ={\tan }^{-1}\left(\frac{y}{x}\right)\dots \dots \dots \dots \dots \dots \left(1\right)$

Substitute the given data in equation (1), and we get,

Substitute the given data in equation (1), and we get,

Substitute the given data in equation (1), and we get,

Substitute the given data in equation (1), and we get,

Therefore the angle made by the vectors is (a)$333.4^o$,(b)$26.6^o$,(c)$333.4^o$,(d)$26.6^o$