A juggler throws a bowling pin straight up with an initial

speed of 8.20 m/s. How much time elapses until the bowling pin

returns to the juggler’s hand?

Short Answer

Expert verified

The total time elapsed by the bowling pin is 1.67 s.

Step by step solution

01

 Step 1: Given data 

Total displacement isy=0m.

The initial velocity isuay=8.2m/sand acceleration is given asay=-9.8m/s2

02

Solution

Using Newton’s second law of motion,

y=uayt+12ayt2

Substituting the values in the above expression will give,

0=8.2m/s×t+12-9.8m/s2×t2t=8.2m/s4.9m/s2t=1.67s

Hence, the time elapsed ist=1.67s

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