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Chapter 1: Q37Q (page 61)

A juggler throws a bowling pin straight up with an initialspeed of 8.20 m/s. How much time elapses until the bowling pinreturns to the juggler’s hand?

Short Answer

Expert verified

The total time elapsed by the bowling pin is 1.67 s.

Step by step solution

01

Given data  

Total displacement isΔy=0m

The initial velocity isuoy=8.2m/s and acceleration is given asay=-9.8m/s2

02

Solution

Using Newton’s second law of motion,

Δy=uoyt+12ayt2

Substituting the values in the above expression will give,

0=8.2m/s×t+12-9.8m/s2×t2t=8.2m/s4.9m/s2t=1.67s

Hence, the time elapsedist=1.67s

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