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Chapter 1: Q39E (page 360)

In a materials testing laboratory, a metal wire made from a new alloy is found to break when a tensile force of 90.8 N is applied perpendicular to each end. If the diameter of the wire is 1.84 mm, what is the breaking stress of the alloy?

Short Answer

Expert verified

Breaking stress of alloy is 3.41x107Pa.

Step by step solution

01

The given data

Given that in a materials testing laboratory, a metal wire made from a new alloy is found to break when a tensile force of 90.8N is applied perpendicular to each end.

The diameter of the wire, d=1.84 mm1 m1000 mm=1.84×10-3 m

Tensile force applied perpendicularly,F⊥=90.8 N

02

Formula used

Breaking stress of wire =F⊥A

Where F⊥is the tensile force applied to an object, A is the area over which force is exerted.

Let d be the diameter of the wire.

A=πd24

03

Find the breaking stress

Area=3.14x1.84x10-3m24=2.66x10-4m2BreakingStress=90.8N2.66x106m2pa=3.41x107pa

Hence, Breaking stress of alloy is3.41x107pa

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