A thin metal disk with mass 2.00x10-3kgand radius2.20cmis attached at its centre to a long fibre. The disk, when twisted and released, oscillates with a period of1.00s. Find the torsion constant of the fibre.

Short Answer

Expert verified

Thetorsionconstantofthefibreis1.9x10-6

Step by step solution

01

Definition of torsion constant

The ratio of the torque to the angle is called the torsion constant. It is denoted by c. For a rigid body formula for torsion constant is

c=4π2IT2

Where,

l = Moment of inertia

T = Time period

02

calculation of torsion constant

Given,

M=2x10-3kgT=1sR=2.2cm

So, I of metal disc is localid="1668148513836" =I=MR22

localid="1668148509505" PutvalueofMandRwegetI=4.84x10-7kg-m2Nowaccordingtoformulac=4π2IT2

localid="1668148518008" putallthevaluesinformulac=4x3.14x3.14x4.84x10-71C=1.9x10-6So,valueoftorsionconstantis1.9x10-6

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