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Chapter 1: Q78P (page 64)

A physics teacher performing an outdoor demonstration suddenly falls from rest off a high cliff and simultaneously shouts “Help.” When she has fallen for 3.0 s, she hears the echo of her shout from the valley floor below. The speed of sound is 340 m/s. (a) how tall is the cliff? (b) If we ignore air resistance, how fast will she be moving just before she hits the ground?

Short Answer

Expert verified

a) Height of the cliff is 532 m.

b) Speed is 14.7 m/s .

Step by step solution

01

Identification of given data

Fallen time (t) = 3.0 s

Speed (v) = 340 m/s

02

Calculation for the height

As we know that

d=vtd=340×3d=1020m

Now in the same time teacher will fall down that distance,

d1=12gt2d1=12×9.81×9d1=44.1m

Now total distance travelled by teacher and sound

dt=d1+ddt=1020+44.1dt=1061.1m

This distance will be equal to twice of the height of cliff

2H=1064.1h=532m

03

Calculation for the speed

d1=vt44.1=v×3v=14.7m/s

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