Sketch the six graphs of the x- and y-components of position, velocity, and acceleration versus time for projectile motion with x0=y0=0and 0<α0<90°.

Short Answer

Expert verified

The diagram for position, velocity, acceleration versus time is

Step by step solution

01

Concept/Significance of projectile.

A projectile is an object that follows a parabolic route when it is projected with velocity not directly upwards but at an angle to the horizontal.

02

sketch of position, velocity, and acceleration versus time for projectile motion.

Consider the x axis. The initial horizontal component of the velocity remains constant during the flight in the absence of air resistance, i.e.,

vx=constant.

It follows from this that the horizontal distance travelled increases linearly with time. The horizontal acceleration is also 0 since there is no force in the direction.

Let's have a look at the next step, which is a little more complicated. For starters, we now have an acceleration of a=-g.

The y coordinate follows a parabolic trajectory, as it does for any projectile motion. Finally, as the flight progresses, the speed drops - initially positive, then negative.

Thus, graph for position, velocity, acceleration versus time is


Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Given two vectors A=4.00i^+7.00j^ and B=5.00i^7.00j^, (a) find the magnitude of each vector; (b) use unit vectors to write an expression for the vector difference AB; and (c) find the magnitude and direction of the vector difference AB. (d) In a vector diagram showA,B and AB, and show that your diagram agrees qualitatively with your answer to part (c).

You normally drive on the freeway between San Diego and Los Angeles at an average speed of 105 km/h (65 mi/h), and the trip takes 1 h and 50 min. On a Friday afternoon, however, heavy traffic slows you down and you drive the same distance at an average speed of only 70 km/h (43 mi/h). How much longer does the trip take?

Hot Jupiters. In 2004 astronomers reported the discovery of a large Jupiter-sized planet orbiting very close to the star HD179949 (hence the term “hot Jupiter”). The orbit was just19 the distance of Mercury from our sun, and it takes the planet only3.09days to make one orbit (assumed to be circular). (a) What is the mass of the star? Express your answer in kilograms and as a multiple of our sun’s mass. (b) How fast (in km>s) is this planet moving?

In an experiment, a shearwater (a seabird) was taken from its nest, flown 5150 km away, and released. The bird found its way back to its nest 13.5 days after release. If we place the origin at the nest and extend the +x-axis to the release point, what was the bird’s average velocity in (a) for the return flight and (b) for the whole episode, from leaving the nest to returning?

The driver of a car wishes to pass a truck that is traveling at a constant speed of20.0m/s(about41mil/h). Initially, the car is also traveling at20.0m/s, and its front bumper is24.0mbehind the truck’s rear bumper. The car accelerates at a constant 0.600m/s2, then pulls back into the truck’s lane when the rear of the car is26.0mahead of the front of the truck. The car islong, and the truck is 21.0m long. (a) How much time is required for the car to pass the truck? (b) What distance does the car travel during this time? (c) What is the final speed of the car?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free