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Chapter 1: Q83 PP (page 99)

About how long does it take a seed launched at 90° at the highest possible initial speed to reach its maximum height? Ignore air resistance. (a) 0.23 s; (b) 0.47 s; (c) 1.0 s; (d) 2.3 s.

Short Answer

Expert verified

(b); It takes 0.47 sfor the seed to reach the maximum height.

Step by step solution

01

Kinematic equation in terms of acceleration, velocity, and initial velocity.

For constant acceleration, the final velocityv is related to the initial velocityu by the expression given below,

v=u+at

02

Determine the time taken to reach the highest point.

The motion is vertical hence the kinematic equation is taken in terms of y-coordinates. As the motion is upwards the sign of g is taken to be negative.

vy=uy+-gt

The final velocity will be zero and the maximum initial velocity is 4.6 m/s, therefore the time taken to reach the highest point is

0=4.6ms-9.8ms2tt=4.6ms9.8ms2=0.47s

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