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Chapter 1: Q84 PP (page 99)

If a seed is launched at an angle of 0° with the maximum initial speed, how far from the plant will it land? Ignore air resistance, and assume that the ground is flat. (a) 20 cm; (b) 93 cm; (c) 2.2 m; (d) 4.6 m.

Short Answer

Expert verified

(b); The seed will land 0.92 mfrom the plant.

Step by step solution

01

Kinematic equations for projectile motion

For horizontal motion,

vx=uxx=xo+uxt

For vertical motion,

vy=uy+gty=yo+uyt+12gt2

02

Calculate the maximum horizontal distance covered by the seed.

Here the initial values of x and y value are zero. The maximum initial horizontal speed is 4.6 m/s. The initial speed in the vertical component is zero. The vertical height is 20 cm.Inserting this data into the vertical displacement equation

y=0+0+12gt2t=2yg=2(2.0m)9.8m/s2=0.20s

Insert this value in the horizontal displacement equation, and we get,

x=0+4.6m/s0.20s=0.92m

Hence, the seed will land 0.92 m from the plant.

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