Chapter 1: Q92PP (page 65)

The velocity of blood in the aorta can be measured directly with ultrasound techniques. A typical graph of blood velocity versus time during a single heartbeat is shown in Fig. P2.92. Which statement is the best interpretation of this graph? (a) The blood flow changes direction at about 0.25 s; (b) the speed of the blood flow begins to decrease at about 0.10 s; (c) the acceleration of the blood is greatest in magnitude at about 0.25 s; (d) the acceleration of the blood is greatest in magnitude at about 0.10 s.

Expert verified

The acceleration of the blood is greater in magnitude at about $0.10 s$ .

Step by step solution

The time intervals at which blood velocity is shown is, $0.10 s, 0.25 s, 0.50 s, 0.75 s, 1.00 s$ .

The given blood velocity is, $0.2 m / s, 0.4 m / s, 0.6 m / s, 0.8 m / s, 1.0 m / s$

The ratio of velocity changes during a certain time period to zero.

The instantaneous acceleration is given by,

$a = \frac{d}{d t} (\frac{d x}{d t}) = \frac{d^{2} x}{d t^{2}} . . . (i)$

The direction of blood flow does not alter.The rate of blood flow decreases.

After $0.2 s$ , the slope flattens off and blood flow speeds up the most.

The slope of graph is steeper about $0.10 s$ ,where acceleration of blood is greatest.

Thus, the acceleration of the blood is greatest about $0.10 s$ .

Unlock Step-by-Step Solutions & Ace Your Exams!

Over 30 million students worldwide already upgrade their learning with Vaia!

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.