A proton is in a box of width L . What must the width of the box be for the ground level energy to be 5.0 MeV, a typical value for the energy with which the particles in a nucleus are bound? Compare your result to the size of a nucleus-that is, on the order of1014m .

Short Answer

Expert verified

The width of the box be0.641×10-14M for the ground level energy to be 5.0 MeV , a typical value for the energy with which the particles in a nucleus are bound and the order of width is same as the diameter of the nucleus.

Step by step solution

01

Define the energy level.

The energy level of a particle of mass in a box of width is:

En=Pn22m=n2h28mL2=n2π2h22mL2(n=1,2,3,...)

02

Determine the width of box.

Given that, energyE1 of photon at ground level is 5.0 MeV .

The energy E1in joule is J

E1=5.00×1.60×10-131=8.00×10-13J

The mass of photon is1.67×10-27kg and value ofh=1.055×10-34J.s .

The width of the box is:

L=nπh2mEn=1π1.055×10-1321.67×10-278.00×10-13=0.641×10-14m

Hence, the width of the box is 0.641×10-14mand order of width is same as the diameter of the nucleus.

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