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Chapter 6: Q5E (page 1275)

A photon has momentum of magnitude 8.24*10-28kgm/s. (a) What is the energy of this photon? Give your answers in joules and in electron volts. (b) What is the wavelength of this photon? In what region of the electromagnetic spectrum does it lie?

Short Answer

Expert verified
  1. The energy of the photon is 2.47*10-19J=1.54eV
  2. The wavelength of this photon is 804nm. It lies in the infrared region.

Step by step solution

01

Formulas used for solving the problem

Energy of the photon is given as:

E = pc

Wavelength of the photon is given as:

λ=hp

02

Determine the energy of the photon

The energy of the photon is calculated as:

E=pc=8.24*10-28*3*108=2.47*10-19J

In electron volt,

E=2.47*10-191.602*10-19=1.54eV

03

Determine the wavelength of this photon

The equation can be given as:

λ=hp

Plug the values,

λ=6.626*10-348.24*10-28=804nm

Thus, the energy of the photon is 2.47*10-19J=1.54eV. The wavelength of this photon is 804nm. It lies in the infrared region.

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