Chapter 5: Q12DQ (page 1151)

There appears to be anambiguity for the case s = 10cm to whether s′ is $s' = + \infty$ and $- \infty$ whether the image is erect or inverted. How is this resolved? Or is it?

Short Answer

Expert verified

Yes, both cases are hold.

Step by step solution

Definition of mirror

The term mirror may be defined as a special type of glass that used to see what behind you.

Explain reason of question

There is no image formed when s = f reflected rays and axis have angle zero degree. s > f in that case real image larger and farmer from the mirror. s' is larger and positive when $s \to f$ . s < f in that case virtual image larger and farther from the mirror.is negative and magnitude larger when $s \to f$ .

Hence, yes these both cases are hold.

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There appears to be anambiguity for the case s = 10cm to whether s′ is $s' = + \infty$ and $- \infty$ whether the image is erect or inverted. How is this resolved? Or is it?

Short Answer

Step by step solution

Definition of mirror

Explain reason of question

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There appears to be anambiguity for the case s = 10cm to whether s′ is s'=+∞and-∞whether the image is erect or inverted. How is this resolved? Or is it?

Short Answer

Step by step solution

Definition of mirror

Explain reason of question

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Circular Motion and Gravitation

Torque and Rotational Motion

Oscillations

Measurements

Fluids

Electrostatics

Study anywhere. Anytime. Across all devices.

There appears to be anambiguity for the case s = 10cm to whether s′ is $s' = + \infty$ and $- \infty$ whether the image is erect or inverted. How is this resolved? Or is it?