Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 5: Q18E (page 1181)

Coherent sources A and B emit electromagnetic waves with wavelength 2.00cm . Point P is 4.86m from A and 5.24m from B. What is the phase difference at P between these two waves?

Short Answer

Expert verified

The phase difference between the two waves at point P is 38πad.

Step by step solution

01

Formula for phase difference

ϕ=∆r*+2πλ

02

Calculate the phase difference

Given: λ=2.0cm=2.0*10-2mrP→A=r1=4.86mrP→B=r1=4.86m

Now, the phase difference is given by

ϕ=∆r*2πλ⇒ϕ=∆(r2-r1)πλ

Plug the given,

ϕ=(5.24-4.86)2.0*10-2=38πrad

Thus, the phase difference between the two waves at point P is38πad .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A concave mirror has a radius of curvature of 34.0cm. (a) What is its focal length? (b) If the mirror is immersed in water (refractive index 1.33), what is its focal length?

An interference pattern is produced by eight equally spaced narrow slits. The caption for Fig. 36.14 claims that minima occur for f =3π/4, π/4, 3π/2 and7π/4. Draw the phasor diagram for each of these four cases, and explain why each diagram proves that there is in fact a minimum. In each case, for which pairs of slits are there totally destructive interference?

If the monochromatic light shown in Fig. 35.5a were replaced by white light, would a two-slit interference pattern be seen on the screen? Explain.

There appears to be anambiguity for the case s = 10cm to whether s′ is s'=+∞and-∞whether the image is erect or inverted. How is this resolved? Or is it?

Monochromatic light is directed at normal incidence on a thin film. There is destructive interference for the reflected light, so the intensity of the reflected light is very low. What happened to the energy of the incident light?
See all solutions

Recommended explanations on Physics Textbooks

Astrophysics

Read Explanation

Electricity

Read Explanation

Classical Mechanics

Read Explanation

Oscillations

Read Explanation

Dynamics

Read Explanation

Fundamentals of Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free