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Chapter 3: Q12E (page 610)

An ideal gas has a density of 1.33×10-6g/cm3atand 20.0°C. Identify the gas.

Short Answer

Expert verified

The ideal gas is Oxygen.

Step by step solution

01

Step 1

The density of gasρ=1.33×10-6g/cm3at the pressureP=1.00×10-3atmat20°C

Therefore, pressure is given at standard atmosphere(atm) it is changed to pascal (Pa) ρ=1.00×10-3×1.013×105Paand temperature is given at Celsius (C) is converted to Kelvin (K) T=293K.

02

Step 2

For the identification of gas, Molar Mass (M) is calculated

p=P.MRT

Here, R is gas constant and the value of R is 8.315 J/mol

Putting all the values, molar mass (M) is

M=ρ×R×TP=1.33×8.315×2931×10−3×1.013×105=31.98g/mol

As Oxygen mole is 32 which is approximately equivalent to 31.98

Hence, thus the given ideal gas is oxygen.

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