When a quantity of monatomic ideal gas expands at a constant pressure of 4×104Pa, the volume of the gas increases fromrole="math" localid="1664296449974" 2×10-3m3to 8×10-3m3. What is the change in the internal energy of the gas?

Short Answer

Expert verified

The change in the internal energy would be 360J.

Step by step solution

01

Find a new relation of internal energy

At constant pressure, the formula for the ideal gas is pΔV=nRΔT.

Where nrepresents the number of moles, Ris the gas constant and has the value of 8.314J/mol.K. The change in temperature is due to the change in volume.

The change in internal energy for any gas is represented by

ΔU=nCVΔTΔU=n(32R)ΔT23ΔU=nRΔT

Clearly, we can write 23U=pU.

02

Put the values and calculate the change in internal energy

Given that p=4×104Pa,V2=8×10-3m3and V1=2×10-3m3.

23ΔU=pΔVΔU=32p(V2-V1)ΔU=32×4×104×(8×10-3-2×10-3)ΔU=360J

So, the change in the internal energy would be 360J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free