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Chapter 3: Q34P (page 642)

You have 750 g of water at 10°Cin a large insulated beaker. How much boiling water at 100°Cmust you add to this beaker so that the final temperature of the mixture will be75°C?

Short Answer

Expert verified

The boiling water is mboiling=1.95kg.

Step by step solution

01

Definition of Mixture

The term mixture may be defined as when two or more substances are combined but not combined chemically

02

Determine the amount of boiling water.

Consider the given data as below.

Initial mass of water, mbefore=750g=0.750kg

Initial temperature, T1=10°C

Boiling temperature, T=100°C

The final temperature, T2=75°C

There is no heat change, heat before adding boiling water is equal to after adding boiling water.

Qbefore=Qaftermbefore×C×δT1=mafter×C×δT2mbefore×C×T2-T1=mafter×C×T-T2

Here, C is the heat capacity.

Substitute known values in the above equation.

0.750kg×75-10°C=mboiling100-75°Cmboiling=1.95kg

Hence, the boiling water is mboiling=1.95kg.

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