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Chapter 3: Q36P (page 642)

One suggested treatment for a person who has suffered a stroke is immersion in an ice-water bath at 0°Cto lower the body temperature, which prevents damage to the brain. In one set of tests, patients were cooled until their internal temperature reached 32°C. To treat a 70 kg patient, what is the minimum amount of ice (at ) you need in the bath so that its temperature remains at 0°C? The specific heat of the human body is 3480J/kg°C, and recall that normal body temperature is37°C

Short Answer

Expert verified

The minimum amount of ice is 3.7 kg.

Step by step solution

01

Definition of heat

The energy transfer from one body to another as a result of a change in temperature can be referred to as heat.

02

Determine the amount of ice

Consider the given data as below.

Mass, m = 70 kg

Heat capacity, C=3480J/kg°C

Change in temperature, δT=32°C-37°C=-5°C

Latent heat of ice, Lf=334×103J/kg

First, calculate the heat quantity of the body

Qbody=m×C×δT=70kg×3480J/kg°C×-5C°=-1.22×106J

Now the latent heat of the ice

Qbody=QiceQice=mice×Lfmice=QiceLf

Substitute known values in the above equation.

mice=1.22×106334×103=3.7kg

Hence, the minimum amount of ice is 3.7 kg.

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