A 75.0-cm-long wire of mass 5.625 g is tied at both ends and adjusted to a tension of 35.0 N. When it is vibrating in its second overtone, find (a) the frequency and wavelength at which it is vibrating and (b) the frequency and wavelength of the sound waves it is producing.

Short Answer

Expert verified

The frequency and wavelength of the string is 136.6Hz and 0.5m respectively and the frequency and wavelength of the string is 136.6Hz and 2.518m respectively

Step by step solution

01

STEP 1 Concept of the frequency for standing wave for the strings fixed at both ends,

Thefrequency for standing wave for the strings is given asf=nv2Lwere,f is the frequency of nth harmonic, v is the velocity of the wave,nnthharmonic (n — 1, 3, 5, ...), L is the length of the pipe.

02

Calculate the frequency and wavelength of the string

For the string

μ=mL=5.625×10-30.75=7.5×10-3kg/mv=Fμ=35N7.5×10-3kg/m=68.313m/s

Second overtone is third harmonic n=3

f3=nv2L=3×65.32m/s2×0.75m=136.6Hzλ=vf=68.32136.6=0.5m

Therefore, the frequency and wavelength of the string is 136.6Hz and 0.5m respectively

03

Step 3 Calculate the frequency and wavelength of the sound

The string is the source of vibration, so, the sound has the same frequency 136.6Hz

λsound=vf=344136.6=2.518m

Therefore, the frequency and wavelength of the string is 136.6Hz and 2.518m respectively

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For cranial ultrasound, why is it advantageous to use frequencies in the kHz range rather than the MHz range?

The intensity due to a number of independent sound sources is the sum of the individual intensities. (a) When four quadruplets cry simultaneously, how many decibels greater is the sound intensity level than when a single one cries? (b) To increase the sound intensity level again by the same number of decibels as in part (a), how many more crying babies are required?

The siren of a fire engine that is driving northward at 30.0 m/s emits a sound of frequency 2000 Hz. A truck in front of this fire engine is moving northward at 20.0 m/s. (a) What is the frequency of the siren’s sound that the fire engine’s driver hears reflected from the back of the truck? (b) What wavelength would this driver measure for these reflected sound waves?

Small speakers A and B are driven in phase at 725 Hz by the same audio oscillator. Both speakers start out 4.50 m from the listener, but speaker A is slowly moved away (Fig. E16.34). (a) At what distance d will the sound from the speakers first produce destructive interference at the listener’s location? (b) If A is moved even farther away than in part (a), at what distance d will the speakers next produce destructive interference at the listener’s

A thin, 75.0cm wire has a mass of 16.5g. One end is tied to a nail, and the other end is attached to a screw that can be adjusted to vary the tension in the wire. (a) To what tension (in newtons) must you adjust the screw so that a transverse wave of wavelength 3.33 cm makes 625 vibrations per second? (b) How fast would this wave travel?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free